Solution :
[tex] \implies \: \sf{ \dfrac{p}{3} > 2(p + 7) } \\ \\ \implies \: \sf{ \frac{p}{3} > 2p + 14 } \\ \\ \implies \: \sf{p> 3( 2p + 14) } \\ \\ \implies \: \sf{p \: > \: 6p +42} \\ \\ \implies \: \sf{p - 6p \: > \: 42} \\ \\ \implies \: \sf{ - 5p \: > \: 42} \\ \\ \implies \: \sf{ - p \: > \: \dfrac{42}{5} } \\ \\ \implies \: \red{\bf{ p \: < \: - \: \dfrac{42}{5} }}[/tex]
