Respuesta :

Stiaen
Hello !

[tex]\sqrt{2n+28}-4\sqrt{n}=0\\\\\sqrt{2n+28}=4\sqrt{n}\\\\\sqrt{2n+28}^2=\left(4\sqrt{n}\right)^2\\\\2n+28=16n\\\\2n-16n=-28\\\\14n=28\\\\\boxed{\boxed{n=2}}[/tex]
20anderpre

Just took the test it. Is n=2