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16-04-2018
Mathematics
contestada
please help!!!!!!!!!!!!!!!
Respuesta :
Professor1994
Professor1994
16-04-2018
x and y vary inversely:
y=k/x
y=8/3 when x=8
8/3=k/8
Solving for k:
8(8/3)=k
64/3=k
k=64/3
y=k/x
y=(64/3)/x
y=(64/3)(1/x)
y=64/(3x)
when x=4→y=64/(3x)=64/(3(4))→y=16/3
Answer: Second Option y=64/(3x); 16/3
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