Respuesta :

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Given: Temperature t = 16 ⁰C;  Specific heat of water c = 4.184 J/ g ⁰C
 Required:  Heat  q = ?     Mass m = 9 grams  Formula to follow  q = mcΔT
q =  (9 grams)(4.184 J/g ⁰C)(16 ⁰C) = 602.496 J             

Answer:

640.46 J

Explanation:

m = 9 g

c = 4.186 J/g C

Rise in temperature = 17 C

Heat used, H = mass x specific heat x rise in temperature

H = 9 x 4.186 x 17 = 640.46 J

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