A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reactants and products be explained?
Cao + H2O ---->Ca(OH)2 Calculate the number of each reactant and the moles of the product that is moles = mass/molar mass The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole the moles of water= 36.04 g/18 g/mol= 2.002moles The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole
The mass of differences of reactant and product can be therefore explained as 1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited
