x^2 + x - 6
------------- <= 0
x - 7
(x + 3)(x - 2)
---------------- <= 0
x - 7
2 critical values are x = -3 and x = 2
if x <= -3 the the function <= 0 so that's one part of the solution
also x >= 2
x must be < 7 if its = 7 then the function is indeterminate. and values between 2 and 7 will give negative valu to function
The answer is choice A.
