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17-02-2018
Physics

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Determine the resistance of a 75-w lightbulb connected to its proper source voltage of 110 v.

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bineleyas bineleyas

17-02-2018

We Know that:
P=V²R
Hence;
We have V=110 v and P=75 w

R=V²/P ⇒ 110²/75
R= 12100/75
R= 161.33 Ω

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