what is y=6x^2+13x-8 in intercept form

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19-12-2017
Mathematics

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what is y=6x^2+13x-8 in intercept form

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tynollette tynollette · Answer 1 · 2017-12-19T19:24:27+01:00

tynollette tynollette

19-12-2017

quadratic function in intercept form is y=a(x-p)(x-q), p and q are the roots.
in this case, factor the expression first:
y=(3x+8)(2x-1)
factor out the coefficients of x: y=3(x+8/3)*2(x-1/2)
so the final answer is y=6(x+8/3)(x-1/2)

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