Calculate the heat when 100.0 ml of 0.500 m hcl is mixed with 300.0 ml of 0.590 m ba(oh)2. assuming that the temperature of both solutions was initially 25.0°c and that the final mixture has a mass of 400 g and a specific heat capacity of 4.18 j/°c · g, calculate the final temperature of the mixture.
It has to be 100mL as total mass = 400g
Moles HCl = 0.05; moles Ba(OH)2 = 0.15
If volume HCl is 100mL then moles HCl = 0.05 and Ba(OH)2 is excess
If 2 moles HCl release 118 kJ then
0.05 moles HCl releases 2.95 kJ
q = cm deltaT
c=4.18 x 10-3 kJ/c.g
DeltaT = q/cm = 2.95/4.18 x 10-3 x 400 = 1.76 degrees rise so final temp = 1.76+ 25
