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An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
N=?

Respuesta :

ejelonubenedict
F = Ke
F = 39200×(25÷100)
F= 9800 N

Answer : F = 9800 N

Explanation :

It is given that,

The spring constant  for the industrial scale at the junkyard, k = 39,200 N/m

Displacement of spring, x = 25 cm = 0.25 m

According to Hooke's law, the force applied on spring is given by the following relation :

F = -k x

Negative sign shows the force is applied in opposite direction.

[tex]F = -39,200\ N/m\times 0.25\ m[/tex]

So, [tex]F=-9800\ N[/tex]

[tex]|F|=9800\ N[/tex]

Hence, this is the required solution.

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