Let's set up an equation:
x plus y is greater than 12
x + y > 12
One of the integers is ten less than twice the other one
x = 2y -10
Time to start solving:
(2y-10) + y > 12
2y + y > 12 + 10
3y > 22
3y=24
y=8
Now its time to find the value of x:
x=2(8) - 10
x=16-10
x= 6
6 + 8 > 12, 6+8 is greater than twelve.
In conclusion we can wrap up that 6 and 8 are the least value integers.
