grasly grasly
  • 17-10-2017
  • Mathematics
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jdoe0001 jdoe0001
  • 17-10-2017
[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r\qquad \begin{cases} r=radius\\ -----\\ r=5x^2 \end{cases}\implies C=2\pi 5x^2\implies C=10\pi x^2 \\\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \begin{cases} r=radius\\ -----\\ r=5x^2 \end{cases}\implies A=\pi (5x^2)^2\implies A=\pi (5^2x^{2\cdot 2}) \\\\\\ A=\pi (25x^4)\implies A=25\pi x^4 [/tex]
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