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A sled is sliding across level, frictionless ground at 3.6 m/s. It hits a rough patch which brings it to a stop in 6.5 m. What is the coefficient of kinetic friction between the sled and the ground in the rough patch

Respuesta :

MathPhys

Answer:

0.10

Explanation:

Method 1: Work energy theorem

W = KE

mgμ d = ½ mv²

μ = ½ v² / (gd)

μ = ½ (3.6)² / (9.8 × 6.5)

μ = 0.10

Method 2: Acceleration and kinematics

∑F = ma

-mgμ = ma

a = -gμ

a = -9.8μ

Given:

s = 6.5 m

u = 3.6 m/s

v = 0 m/s

v² = u² + 2as

0² = (3.6)² + 2 (-9.8μ) (6.5)

μ = 0.10

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