aliahmaesandoval0 aliahmaesandoval0
  • 19-02-2024
  • Chemistry
contestada

A 2.00 L of certain gas occupies a pressure of 740.0 mmHg. What is its volume in L at standard pressure?

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ph869406 ph869406
  • 19-02-2024

Explanation:

Step 1: Convert the initial pressure to atm: P1 = 740.0 mmHg * (1 atm / 760 mmHg) = 0.9737 atm

Step 2: Use Boyle's Law to find the final volume: P1V1 = P2V2 (0.9737 atm)(2.00 L) = (1 atm)(V2)

Step 3: Solve for V2: V2 = (0.9737 atm)(2.00 L) / (1 atm) = 1.9474 L So, the volume of

the gas at standard pressure is 1.9474L

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