duulceemalpica duulceemalpica

17-08-2017
Chemistry

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What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP? A. 10.5 L B. 428.1 L C. 584.0 L D. 127.6 L

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ILOVEGalGadot ILOVEGalGadot

17-08-2017

1.55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L
So answer A.

Answer Link

CollinStanley CollinStanley

17-08-2017

(55 L) x (273 K) / (500 K) x (4.25 atm) / (1.00 atm) = 127.6 L

Answer Link

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