Respuesta :

boldeagle
-5g - 3/h-3 + 7g +9/h-3 = -5g + 7g -3/h-3 + 9/h-3 = 2g + (9 - 3)/(h-3) = 
= 2g + 6/(h-3) if we want it as one fraction it would be:

2g + 6/(h-3) = [2g(h-3) + 6]/(h-3) = [tex] \frac{2gh - 6gh + 6}{h-3} [/tex]

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