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A 3.15 kg fish is attached to the lower end of a vertical spring that has negligible mass and force constant 855 N/m . The spring initially is neither stretched nor compressed. The fish is released from rest.

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BlueSky06
In this item, we are asked to determine the length at which the spring will be stretched given that a fish is attached to one of its end. To answer this, first, we must calculate for the weight of the fish.
                              Weight = (3.15 kg)(9.8 m/s²)
                              Weight = 30.87 N
Then, divide the calculated weight by the given force constant to determine the length.
                            Length = (30.87 N)/(855 N/m) = 0.036 m


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