Given: KL is a tangent to the circle.
LM is another tangent to the circle.
We can use the tangent meeting at an external point theorem.
Theorem: The tangent segments to a circle from an external point are equal.
Thus, we can say KL = LM, as they lie on a common circle, and are tangents to such circle.
4x - 2 = 3x + 3
4x - 3x = 3 + 2
x = 5
Since LM is 3x + 3, we can substitute the value of x to LM to render:
3(5) + 3 = 18
Thus, LM = KL = 18 units.
