Answer:
Value of x is 3.
Step-by-step explanation:
Given : TQ ≅ QR or TQ = QR
To find: Value of x
Consider,
In Δ STQ and Δ SRQ
∠STQ = ∠SRQ = 90°
SQ ≅ SQ (common)
TQ ≅ RQ (given)
⇒ Δ STQ and Δ SRQ are congruent by RHS congruent rule.
By CPCT (corresponding parts of congruent triangle)
∠TSQ = ∠RSQ
2x + 24 = 30
2x = 30 - 24
2x = 6
x = 3
Therefore, Value of x is 3.
