Write an inverse variation to model the situation and answer the question. Two rectangular fields have the same area. One measures 75 yd by 60 yd. If the other has a length of 72 yd, what is its width? Explain your answer and the steps you have taken to obtain it.
Step 1: Use the equation y = [tex] \frac{k}{s} [/tex] in solving inverse variation problems y = [tex] \frac{k}{s} [/tex] ⇒ w = [tex] \frac{k}{l} [/tex]
w = width l = length k = area
Step 2. Find the value of k by substituting the given information, where: w = 60 yd l = 75 yd
60 = [tex] \frac{k}{75} [/tex] k = 4500 yd²
Step 3. Rewrite the standard equation by substituting the value of k = 4500 yd²
w = [tex] \frac{4500}{l} [/tex]
Step 4. Substitute l = 72 yd to find the width of the second field w = [tex] \frac{4500}{72} [/tex] w = 62.5 yd
