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  • 17-05-2017
  • Chemistry
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What is the ph of a 0.15 m solution of ammonium chloride?

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  • 17-05-2017
 Best Answer:  (a) 
8.9 x 10^-7 = x^2 / 0.15-x 
x = [OH-] = 0.00037 M 
pOH = 3.4 
pH = 14 - 3.4 = 10.6 

(b) 
Ka = Kw/Kb = 5.6 x 10^-10 = x^2 / 0.20-x 
x = [H+] = 0.000011 M 
pH = 5.0
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