angie176
angie176
16-05-2017
Chemistry
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How many atoms are present In 179.0 g of irídium
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davinioza
davinioza
16-05-2017
179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms / 1 mol ) = 5.61 x 10^23 atoms of iridium
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