Answer:
There are 72 g of carbon in 0.500 mol of sucrose.
Explanation:
The sucrose molecule has the formul C₁₂H₂₂O₁₁.
Each molecule of sucrose has 12 atoms of carbon.
Each carbon atom weights 12 a.u.
Each mole of sucrose weights 342.30 g.
Each mole of carbon weights 12 g.
12 carbons weight 144 g.
Therefore, the weight percentage of carbon in each mole of sucrose is:
%C = 144/342.30 x 100%
%C = 42.1%
0.500 mol of sucrose weights 342.30 g/2 = 171.15 g.
42.1% x 171.15 g = 72 g
