Answer:
[tex]h(1)=1[/tex] and [tex]h(4)=5[/tex]
Step-by-step explanation:
We are given the function,
[tex]h(x)=\left\{\begin{matrix}x^2,&x<0\\3-x,&0\leq x<1\\x^2,&1\leq x\leq 3\\5,&x>3\end{matrix}\right.[/tex]
Since, when x= 1, the function is [tex]h(x)=x^2[/tex]
Then, [tex]h(1)=(1)^2= 1[/tex]
Also, when x= 4, the function is [tex]h(x)=5[/tex]
That is, [tex]h(4)=5[/tex]
Hence, we get that,
[tex]h(1)=1[/tex]
[tex]h(4)=5[/tex]
