eknight eknight
  • 17-04-2017
  • Mathematics
contestada

Solve the simultaneous equations, 2x+4y = 1
3x-5y = 7

Respuesta :

irspow
irspow irspow
  • 17-04-2017
For a solution to exist the x and y values must be equal at that point.

I'll solve both for y first (and there are other ways to do this of course)

2x+4y=1, 4y=1-2x, y=(1-2x)/4

3x-5y=7, -5y=7-3x, y=(3x-7)/5

Since y=y at the solution point we can say:

(1-2x)/4=(3x-7)/5  cross multiplying...

5-10x=12x-28

-22x=-33

x=3/2 or if you prefer 1.5, now we can solve for y using either origianl equation...

2(1.5)+4y=1

3+4y=1

4y=-2

y=-0.5

So the solution is the point (1.5, -0.5)
Answer Link

Otras preguntas

Which is an example of codominance?
??????????.....:::v???
draw the structures pf the ions ni2+ and fe3+ as they exist in aqueous solution in octahedral shape.
What is the surface area of the composite figure? (Use 3.14 for π .) 954.56 in. 2 1,356.48 in. 2 1,155.52 in. 2 1,557.44 in. 2
To win at lotto in a certain state one must correctly select 6 numbers from a collection of 50 members . The order in which the selections is made does not matt
Multiply or divide as indicated. x 2 • x 5
If you take pen off lessons apps 4:15 p.m. and it ends at 5:50 p.m. how long does he practiss
I need help with this please
Caesar began his rule of Rome as a member of the First Triumvirate. How did he become Rome’s sole leader?
What is the area of the parallelogram?