ayato2005 ayato2005
  • 20-05-2023
  • Mathematics
contestada

¿Cuál es el valor de 6 – (3x + 1) + 2x^2, cuando x = 4?

Respuesta :

sanadahamed123456789
sanadahamed123456789 sanadahamed123456789
  • 20-05-2023

Answer:

Para encontrar el valor de la expresión 6 - (3x + 1) + 2x^2 cuando x = 4, sustituimos el valor de x en la expresión y evaluamos:

6 - (3x + 1) + 2x^2

= 6 - (3 * 4 + 1) + 2 * 4^2

= 6 - (12 + 1) + 2 * 16

= 6 - 13 + 32

= -7 + 32

= 25

Por lo tanto, cuando x = 4, el valor de la expresión 6 - (3x + 1) + 2x^2 es igual a 25.

Step-by-step explanation:

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