t is time afer houw many years
so
A=amout so we want to solve when A=7890
[tex]7890=6300e^{0.045t}[/tex]
divide both sides by 6300
[tex] \frac{7890}{6300} =e^{0.045t}[/tex]
take ln of both sides
[tex] ln(\frac{7890}{6300}) =0.045t[/tex]
divide both sides by 0.045 and evaluate using calculator
[tex] \frac{ln(\frac{7890}{6300})}{0.045} =t[/tex]
5.00103=t
after about 5 years
5 years after 2000 is 2005
wait, it is 5.00103, not 5, so it is just after 2005 so the beginning of 2006
answer is C
