Answer: The Molarity of chloride ion in the solution is 0.1344 m.
Explanation:
For this question we first have to find the no. of moles of the given compound.
moles of Aluminium chloride is (n)= 1.5/133.5=0.0112. (given mass/molecular mass)
no of chloride ions present in 1 mole of this given compound = 3
moles of chloride ions present in 0.0112 moles of compound = 0.0112x3=0.0336
molarity of CL ion is = 0.0336/(250/1000)=0.1334 m
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