20-02-2017
Mathematics

contestada

cos b + sin b × tan b = sec b

Respuesta :

ChandrikaP ChandrikaP

20-02-2017

cosb+sinb*tanb=secb

take LHS first
cosb+sinb*sinb/cosb----------tanb=sinb/cosb
cosb+(sinb)^2/cosb
[cos^2b+sin^2b]/cosb
1/cosb=secb -------------- cos^2b+sin^2b=1
LHS=RHS

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