Respuesta :

[tex]\begin{gathered} \frac{p^3q^5r^2}{pq^3r^2}=\frac{p\cdot p\cdot\cancel{p}\cdot\cancel{q\cdot q\cdot q}\cdot q\cdot q\cdot\cancel{r\cdot r}}{\cancel{p}\cdot\cancel{q\cdot q\cdot q}\cdot\cancel{r\cdot r}} \\ \frac{p^3q^5r^2}{pq^3r^2}=\frac{p^{}\cdot p\cdot q\cdot q}{1}=\frac{p^2q^2}{1}=p^2q^2 \end{gathered}[/tex][tex]\begin{gathered} \text{ The answer is} \\ \frac{p^3q^5r^2}{pq^3r^2}=p^2q^2 \end{gathered}[/tex]