Greetings from Brasil...
According to the statement
A + B + C + D + E = 47
making B the multiple of 9
A + 9B + C + D + E = 47
as the other 4 numbers are the same, let's call it A
A + 9B + A + A + A = 47
4A + 9B = 47 assigning values to B, we have
B = 1 ⇒ A ∉ ℤ
B = 2 ⇒ A ∉ ℤ
B = 3 ⇒ A = 5
B = 4 ⇒ A ∉ ℤ
B = 5 ⇒ A ∉ ℤ
B = 6 → from now on, A will be negative
Then
A = 5 and B = 3
Multiplying all numbers:
A·9B·A·A·A = 9A⁴B = 9·5⁴·3 = 16875
