Explanation
[tex] \frac{ - 4(x + h)^{2} - 6(x + h) + 7 + 4 {x}^{2} + 6x - 7 }{h} \\ \frac{ - 4 {x}^{2} - 8hx - 4 {h}^{2} - 6x - 6h+ 7 + 4 {x}^{2} + 6x - 7 }{h} \\ \frac{ { - 4h}^{2} - 8hx - 6h }{h} \\ \frac{h( - 4h - 8x - 6)}{h} \\ - 4h - 8x - 6 \\ since \: you \: given \: h \: approaches \: 0 \\ - 4(0) - 8x - 6 \\ -8x - 6[/tex]
Answer
-8x-6
