Answer:
3.125 inches
Step-by-step explanation:
The beam is clearly not uniformly loaded, so there doesn't appear to be any appropriate interpretation of the problem other than to evaluate the function for the given value of x.
Function evaluation
Use 5 for the value of x and do the arithmetic.
[tex]d(x)=\dfrac{1}{200}x^2(x-10)^2\\\\d(5)=\dfrac{5^2(5-10)^2}{200}=\dfrac{25(25)}{200}=\boxed{3.125}[/tex]
The deflection of the beam is 3.125 inches when force is applied 5 feet from the end.
