iambadatmath1234 iambadatmath1234
  • 20-08-2022
  • Mathematics
contestada

need helpppppppp

plssssssssssssssssssssssssssssssss

need helppppppppplssssssssssssssssssssssssssssssss class=

Respuesta :

Medunno13
Medunno13 Medunno13
  • 20-08-2022

Answer:

Option 2, 9<V<1944

Step-by-step explanation:

Part 1

[tex]V=\frac{1}{2}(x)(3x)(6x)=9x^3[/tex]

Part 2

[tex]9(1)^3 < V<9(6)^3 \\ \\ 9<V<1944[/tex]

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