If Points A, B, C, D, and E are collinear and AC = 16. x is 3, AB is 10, BD is 14, CE is 17.
Collinear
22. x
AC=AB+BC
Hence:
x+7+2x=16
3x=9
x=9/3
x=3
23. AB
AB=x+7
AB=3+7
AB=10
24. BD
BD=BC+CD
BD=2x+3x-1
BD=5x-1
BD=5(3)-1
BD=15-1
BD=14
25. CE
CE=CD+DE
CE=3x-1+2x+3
CE=5x+2
CE=5(3)+2
CE=15+2
CE=17
Therefore if Points A, B, C, D, and E are collinear and AC = 16. x is 3, AB is 10, BD is 14, CE is 17.
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