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Students in a chemistry lab are making the compound cobalt(II) carbonate.
It can be made by reacting sodium carbonate solution with cobalt(II) chloride solution. Calculate the volume of 2.0 mol/L cobalt(II) chloride solution required to completely react with 250 mL of 1.5 mol/L sodium carbonate.

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The volume of 2.0 mol/L cobalt(II) chloride solution required for the reaction is 187.5 mL

How to determine the mole of Na₂CO₃ in the solution

  • Volume of Na₂CO₃ = 250 mL = 250 / 1000 = 0.25 L
  • Molarity of Na₂CO₃ = 1.5 mol/L
  • Mole of Na₂CO₃ = ?

Mole = molarity × volume

Mole of Na₂CO₃ = 1.5 × 0.25

Mole of Na₂CO₃ = 0.375 mole

How to determine the mole of CoCl₂ needed

Balanced equation

CoCl₂ + Na₂CO₃ -> CoCO₃ + 2NaCl

From the balanced equation above,

1 mole of Na₂CO₃ reacted with 1 mole of CoCl₂.

Therefore,

0.375 mole of Na₂CO₃ will also react with 0.375 mole of CoCl₂.

How to determine the volume of CoCl₂

  • Molarity of CoCl₂ = 2 mol/L
  • Mole of CoCl₂ = 0.375 mole
  • Volume of CoCl₂ = ?

Volume = mole / molarity

Volume of CoCl₂ = 0.375 / 2

Volume of CoCl₂ = 0.1875 L

Multiply by 1000 to express in mL

Volume of CoCl₂ = 0.1875 × 1000

Volume of CoCl₂ = 187.5 mL

Learn more about stoichiometry:

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