Respuesta :

Answer:

A

Step-by-step explanation:

[tex]\frac{x}{x-5}[/tex] × [tex]\frac{2x}{x+4}[/tex] ( no factors cancel on numerator/ denominator )

= [tex]\frac{x(2x)}{(x-5)(x+4)}[/tex]

= [tex]\frac{2x^2}{x^2-x-20}[/tex]