Answer:
[tex]\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0][/tex]
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
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-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)
