Answer:
(0, -3) and (3, 0)
Explanation:
1st equation: y = x² -2x - 3
2nd equation : y = x - 3
Using substitution method:
x² -2x - 3 = x - 3 exchange sides
x² - 2x - x - 3 + 3 = 0 simplify
x² - 3x = 0 take common factor
x(x - 3) = 0 simplify
x = 0, 3
Solve for y:
when x is 0, y = x - 3 = 0 - 3 = -3
when x is 3, y = x - 3 = 3 - 3 = 0
