RomanFlare
RomanFlare RomanFlare
  • 19-05-2022
  • Mathematics
contestada

Solve the system of the linear equations with three variables:
6x + 4y + z = 12
6x + 4y + 2z = 12
6x + 4y + 3z = 12

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 19-05-2022

Answer:

z = 0

y = -3x/2 + 3

Step-by-step explanation:

6x + 4y + z = 12

6x + 4y + 2z = 12

6x + 4y + 3z = 12

Second equation minus first equation:

z = 0

If you plug in z = 0 in all the original equations, you get a single equation:

3x + 2y = 6

The best you can do is to solve for y in terms of x.

y = -3x/2 + 3

Answer:

z = 0

y = -3x/2 + 3

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