The minimum number of bits the address bus must have in the byte addressable memory system is 12
How to determine the minimum number of bits?
The memory size is given as;
Size = 4 KiB
Convert to bytes
Size = 4 * 2^10 bytes
Express 4 as 2^2
Size = 2^2 * 2^10 bytes
Multiply
Size = 2^12 bytes
The minimum number of bits is then calculated as;
2^n = Size
This gives
2^n = 2^12
Cancel out the base (2)
n = 12
Hence, the minimum number of bits is 12
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