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Questions #7 and 8:

Part 1 of 2: An ideal gas, initially at a volume of 6.22222 L and pressure of 9 kPa, undergoes isothermal expansion until its volume is 8 L and its pressure is 7 kPa. Calculate the work done by the gas during this process. Answer in units of J.

Part 2 of 2: Find the heat added to the gas during this process. Answer in units of J.

Respuesta :

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(a) The work done by the ideal gas during the isothermal exapnsion process is -3.556 J.

(b) The heat added to the gas during this process is 3.556 J.

Work done by the ideal gas

The work done by an ideal gas in isothermal expansion is change in pressure and volume of the gas. The change in the internal energy of the gas is zero.

The work done by the given ideal gas is calculated as follows;

W = ΔPV

where;

  • ΔP is change in pressure of the gas
  • ΔV is change in volume of the gas

W = (P₂ - P₁)(V₂ - V₁)

W = (7kPa - 9kPa)(8L - 6.222L)

W = -3.556 kPa.L

1 kPa.L = 1 J

W = -3.556 J

Heat added to the process

ΔU = q + w

where;

  • ΔU is change in internal energy = 0

0 = q + (-3.556)

q = 3.556 J

Learn more about isothermal expansion here: https://brainly.com/question/15447045

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