prashansikar
prashansikar prashansikar
  • 17-03-2022
  • Mathematics
contestada

if a=6^x ,b= 6^y ,a^y.b^x=36 then prove that : xy=1​

Respuesta :

jimthompson5910 jimthompson5910
  • 17-03-2022

Raise both sides of the first equation to the exponent y

[tex]a = 6^x\\\\a^y = (6^x)^y\\\\a^y = 6^{xy}\\\\[/tex]

Raise both sides of the second equation to the exponent of x.

[tex]b = 6^y\\\\b^x = (6^y)^x\\\\b^x = 6^{xy}\\\\[/tex]

Multiplying them gets us

[tex]a^y*b^x = 36\\\\6^{xy}*6^{xy} = 6^2\\\\6^{xy+xy} = 6^2\\\\6^{2xy} = 6^2\\\\2xy = 2\\\\xy = 2/2\\\\xy = 1\\\\[/tex]

This concludes the proof.

Answer Link
ximena72905 ximena72905
  • 17-03-2022
Xy Equals 1 I used a calculator
Answer Link

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