chloeomness
chloeomness chloeomness
  • 17-02-2022
  • Mathematics
contestada

20 points please answer quick

20 points please answer quick class=

Respuesta :

semsee45
semsee45 semsee45
  • 17-02-2022

Answer:

[tex]x^8\sqrt[3]{x}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{x^{25}}[/tex]

Apply the exponent rule [tex]a^{b+c}=a^b \cdot a^c[/tex]

[tex]\implies \sqrt[3]{x^{(24+1)}}=\sqrt[3]{x^{24}x^1}=\sqrt[3]{x^{24}x}[/tex]

Apply the radical rule [tex]\sqrt{ab} =\sqrt{a}\sqrt{b}[/tex]:

[tex]\implies =\sqrt[3]{x^{24}x}=\sqrt[3]{x^{24}}\sqrt[3]{x}[/tex]

Apply the radical rule [tex]\sqrt[a]{x^b} =x^{\frac{b}{a}}[/tex]:

[tex]\implies \sqrt[3]{x^{24}}\sqrt[3]{x}=x^{\frac{24}{3}}\sqrt[3]{x}=x^8\sqrt[3]{x}[/tex]

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