averybechtold averybechtold
  • 18-12-2021
  • Physics
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I need help asap! Will give brainliest

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Аноним Аноним
  • 06-02-2022

[tex]\\ \tt\hookrightarrow \dfrac{(3\times 10^4kg)(4\times 10^4m)}{6\times 10^4s)}[/tex]

[tex]\\ \tt\hookrightarrow \dfrac{12\times 10^8kgm}{6\times 10^4s}[/tex]

[tex]\\ \tt\hookrightarrow 2kgm/s[/tex]

We have calculated momentum

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