randypressley0 randypressley0
  • 16-12-2021
  • Mathematics
contestada

Write g(x) = 4x2 + 88x in vertex form.

The function written in vertex form is g(x) =
(x +11)2 +

Respuesta :

jimrgrant1 jimrgrant1
  • 16-12-2021

Answer:

g(x) = 4(x + 11)² - 484

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

g(x) = 4x² + 88x ( factor out 4 from each term )

      = 4(x² + 22x)

Using the method of completing the square

add/subtract ( half the coefficient of the x- term)² to x² + 22x

g(x) = 4(x² + 2(11)x + 121 - 121)

      = 4(x + 11)² - 4(121)

      = 4(x + 11)² - 484 ← in vertex form

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