Answer:
[tex]\frac{1}{2x-3}[/tex]
Step-by-step explanation:
([tex]\frac{f}{g}[/tex] )(x)
= [tex]\frac{f(x)}{g(x)}[/tex]
= [tex]\frac{x+1}{2x^2-x-3}[/tex] ( factorise the denominator )
= [tex]\frac{x+1}{(2x-3)(x+1)}[/tex] ← cancel the common factor (x + 1) on numerator/ denominator
= [tex]\frac{1}{2x-3}[/tex]
