Answer:
0.296 M
Explanation:
What is the molar concentration of a solution prepared by dissolving 3.05 grams of sodium acetate in enough water to prepare 3.43 x 102 mL of the solution
sodium acetate NaCH3COO has molar mas of
23 + 12 +24 + 1 +32 = 92 g/mol
3.05 g is 3.05 g/ 92 g/mol = 0.0328 moles
it is distributed over 102 mL = 0.102 L
its concentration is 0.0328/ 0.102 =0.296 M Mhttps://brainly.com/question/25586315?answering=true&answeringSource=feedPublic%2FhomePage%2F3#
