Answer: y=((3/2)c - ax)/b or [y = (3c-2ax)/2b]
Step-by-step explanation:
2/3(ax+by)=c solve for y
(2/3)ax+(2/3)by=c
(2/3)by=c -(2/3)ax
(3/2)(2/3)by=(3/2)c -(3/2)*(2/3)ax
by=(3/2)c - ax
y=((3/2)c - ax)/b or [y = (3c-2ax)/2b]
