Step-by-step explanation:
[(3x − 6) (4x² − 1)] – [(2x − 4) (4x² + 4x + 1)]
>[3(x-2) (2x+1)(2x-1)]-[2(x-2)(4x²+2x+2x+1)
>[3(x-2)(2x+1)(2x-1)]-[2(x-2){2x(2x+1)+1(2x+1)}]
> 3(x-2)(2x+1)(2x-1)-2(x-2)(2x+1)²
> (x-2)(2x+1) [3(2x-1)-2(2x+1)]
> (2x²-3x-2)(6x-3-4x-2)
> (2x²-3x-2)(2x-5).
hope this helps you.
